Pembahasan Soal Ujian Profesi Aktuaris
SOAL
Untuk (x) dan (y) yang saling bebas, diberikan sebagai berikut:
- \({\bar a_x} = 10,06\)
- \({\bar a_y} = 11,95\)
- \({\bar a_{\bar x\bar y}} = 12,59\)
- \({\bar A_{x\mathop y\limits^| }} = 0,09\)
- \(\delta = 0,07\)
Hitunglah \({\bar A_{\mathop x\limits^| y}}\)
- 0,15
- 0,20
- 0,25
- 0,30
- 0,35
| Step 1 | \({\bar a_{xy}} = {\bar a_x} + {\bar a_y} – {\bar a_{\bar x\bar y}}\) \({\bar a_{xy}} = 10,06 + 11,95 – 12,59\) \({\bar a_{xy}} = 9,42\) |
| Step 2 | \({\bar A_{xy}} = 1 – \delta {\bar a_{xy}}\) \({\bar A_{xy}} = 1 – 0,07\left( {9,42} \right)\) \({\bar A_{xy}} = 0,3406\) |
| Step 3 | \({\bar A_{xy}} = {\bar A_{x\mathop y\limits^| }} + {\bar A_{\mathop x\limits^| y}}\) \({\bar A_{\mathop x\limits^| y}} = 0,3406 – 0,09\) \({\bar A_{\mathop x\limits^| y}} = 0,2506\) \({\bar A_{\mathop x\limits^| y}} \cong 0,25\) |
| Jawaban | c. 0,25 |