Pembahasan Ujian PAI: A70 – No. 6 – November 2014

• \({H_{NA}} = \frac{{{s_i}}}{{{r_i}}}\)
• \({\lambda _{KM}} = 1 – {H_{NA}}\)

\({S_{25}}(14) = \prod\limits_{j = 1}^{12} {{\lambda _{KM}}} = \left( {\frac{{24}}{{25}}} \right)\left( {\frac{{22}}{{25}}} \right)…\left( {\frac{2}{4}} \right)\left( {\frac{1}{2}} \right) = \frac{{187}}{{2520}}\)
\({S_{25}}(20) = {e^{\frac{{20}}{{16}}\ln \left( {{S_{25}}(14)} \right)}} = {e^{\frac{{20}}{{16}}\ln \left( {\frac{{187}}{{2520}}} \right)}} = 0,03873\)