Pembahasan Ujian PAI: A60 – No. 19 – Mei 2018

• Seleksi 1 tahun
• \({\ddot a_{x:\left. {\overline {\,  n \,}}\! \right| }} = 21,854\)
• \({\ddot a_{\left[ x \right]:\left. {\overline {\,  n \,}}\! \right| }} = 22,167\)
• \({P_{\left[ x \right]}} = \left( {1 + k} \right){p_x}\)

\(= 1 + v \cdot {p_{\left[ x \right]}} + {v^2} \cdot {p_{\left[ x \right]}} \cdot {p_{x + 1}} + …\)
\(= 1 + v \cdot \left( {1 + k} \right){p_x} + {v^2} \cdot \left( {1 + k} \right){p_x} \cdot {p_{x + 1}} + …\)
\(= \left( {1 + k} \right)\left[ {\underbrace {1 + v \cdot {p_x} + {v^2} \cdot {p_x} \cdot {p_{x + 1}} + …}_{{{\ddot a}_{x:\left. {\overline {\, n \,}}\! \right| }}}} \right] – k\)

\(22,167 = \left( {1 + k} \right) \cdot 21,854 – k\)
\(22,167 = 21,854 + 21,854k – k\)
\(22,167 – 21,854 = 20,854k\)
\(\frac{{0,313}}{{20,854}} = k\)
\(0,015 = k\)