Pembahasan Soal Ujian Profesi Aktuaris
SOAL
Diketahui kejadian A, B dan C memenuhi hubungan sebagai berikut :
\(A \cap B'{\rm{ }} = \phi ,B \cap C'{\rm{ }} = \phi ,{\rm{ }}Pr(A’ \cap B){\rm{ }} = x,{\rm{ }}Pr(B’ \cap C){\rm{ }} = y,{\rm{ }}Pr\left( C \right){\rm{ }} = z\)Maka Pr(A) sama dengan …
- x + y + z
- x + y – z
- y + z – x
- x – y + z
- z – x – y
Diketahui | \(A \cap B'{\rm{ }} = \phi ,B \cap C'{\rm{ }} = \phi ,{\rm{ }}Pr(A’ \cap B){\rm{ }} = x,{\rm{ }}Pr(B’ \cap C){\rm{ }} = y,{\rm{ }}Pr\left( C \right){\rm{ }} = z\) |
Rumus yang digunakan | \(\Pr (B \cup C’) = \Pr (B) + \Pr (C’) – \Pr (B \cap C’)\) \(\Pr (A \cup B’) = \Pr (A) + \Pr (B’) – \Pr (A \cap B’)\) |
Proses pengerjaan | \(\Pr (B \cup C’) = \Pr (B) + \Pr (C’) – \Pr (B \cap C’)\) \(\Leftrightarrow 1 – \Pr (B’ \cap C) = \Pr (B) + \Pr (C’) – 0\) \(\Leftrightarrow 1 – y = \Pr (B) + (1 – z)\) \(\Leftrightarrow z – y = \Pr (B)\) \(\Pr (A \cup B’) = \Pr (A) + \Pr (B’) – \Pr (A \cap B’)\) \(\Leftrightarrow 1 – \Pr (A’ \cap B) = \Pr (A) + \Pr (B’) – 0\) \(\Leftrightarrow 1 – x = \Pr (A) + (1 – z + y)\) \(\Leftrightarrow z – x – y = \Pr (A)\) |
Jawaban | e. z – x – y |