| Misalkan |
P menyatakan premi netto tahunan |
| Step 1 |
\({\ddot a_{x:\left. {\overline {\, n \,}}\! \right| }} = \frac{{1 – {A_{x:\left. {\overline {\, n \,}}\! \right| }}}}{d}\)
\({\ddot a_{x:\left. {\overline {\, n \,}}\! \right| }} = \frac{{1 – \left( {{A_{\mathop x\limits^| :\left. {\overline {\, n \,}}\! \right| }} + {A_{x:\mathop {\left. {\overline {\, n \,}}\! \right| }\limits^| }}} \right)}}{{\left( {iv} \right)}}\)
\({\ddot a_{x:\left. {\overline {\, n \,}}\! \right| }} = \frac{{1 – \left( {{A_{\mathop x\limits^| :\left. {\overline {\, n \,}}\! \right| }} + {A_{x:\mathop {\left. {\overline {\, n \,}}\! \right| }\limits^| }}} \right)}}{{\left( {iv} \right)}}\) |
| Step 2 |
\({\bar A_{x:\left. {\overline {\, n \,}}\! \right| }} = \left( {{{\bar A}_{\mathop x\limits^| :\left. {\overline {\, n \,}}\! \right| }} + {{\bar A}_{x:\mathop {\left. {\overline {\, n \,}}\! \right| }\limits^| }}} \right)\)
\({\bar A_{x:\left. {\overline {\, n \,}}\! \right| }} = \frac{i}{\delta }\left( {{A_{\mathop x\limits^| :\left. {\overline {\, n \,}}\! \right| }}} \right) + {}_n{E_x}\)
\(0,192 = \frac{{0,05}}{{\ln (1,05)}}\left( {{A_{\mathop x\limits^| :\left. {\overline {\, n \,}}\! \right| }}} \right) + 0,172\)
\({A_{\mathop x\limits^| :\left. {\overline {\, n \,}}\! \right| }} = 0,01951616567\)
\({A_{\mathop x\limits^| :\left. {\overline {\, n \,}}\! \right| }} \cong 0,0195\) |
|
\({\ddot a_{x:\left. {\overline {\, n \,}}\! \right| }} = \frac{{1 – \left( {{A_{\mathop x\limits^| :\left. {\overline {\, n \,}}\! \right| }} + {}_n{E_x}} \right)}}{{\left( {iv} \right)}}\)
\({\ddot a_{x:\left. {\overline {\, n \,}}\! \right| }} = \frac{{1 – \left( {0,0195 + 0,172} \right)}}{{\left( {\frac{{0,05}}{{1,05}}} \right)}}\)
\({\ddot a_{x:\left. {\overline {\, n \,}}\! \right| }} = 16,9785\) |
| Maka |
\(P = \frac{{B{{\bar A}_{x:\left. {\overline {\, n \,}}\! \right| }}}}{{{{\ddot a}_{x:\left. {\overline {\, n \,}}\! \right| }}}}\)
\(P = \frac{{1.000(0,192)}}{{16,9785}}\)
\(P = 11,30841947\)
\(P \cong 11,3\) |
| Jawaban |
b. 11,3 |
