Pembahasan Ujian PAI: A70 – No. 2 – Juni 2015

• \({S_{25}}\left( {11} \right) = \prod\limits_{j = 1}^9 {\frac{{{r_j} – {s_j}}}{{{r_j}}}} \)
• \(\hat S\left( {11} \right) = {e^{ – \hat H(11)}}\)

\({S_{25}}\left( {11} \right) = \prod\limits_{j = 1}^9 {\frac{{{r_j} – {s_j}}}{{{r_j}}}} \)
\({S_{25}}\left( {11} \right) = 1\left( {\frac{{24}}{{25}}} \right)\left( {\frac{{22}}{{24}}} \right)\left( {\frac{{17}}{{21}}} \right)\left( {\frac{{13}}{{15}}} \right)\left( {\frac{{10}}{{13}}} \right)\left( {\frac{7}{8}} \right)\left( {\frac{6}{7}} \right)\left( {\frac{5}{6}} \right) = 0,2968253968\)
\(\hat H(11) = \sum\limits_{j = 1}^9 {\frac{{{s_j}}}{{{r_j}}}} = \frac{1}{{25}} + \frac{2}{{24}} + \frac{4}{{22}} + \frac{2}{{15}} + \frac{3}{{13}} + \frac{1}{8} + \frac{1}{7} + \frac{1}{6} = \frac{{8677}}{{7800}}\)
\(\hat S\left( {11} \right) = {e^{ – \hat H(11)}} = {e^{ – {\rm{ }}\frac{{8677}}{{7800}}}} = 0,3287571662\)
\({S_{25}}\left( {11} \right) – \hat S\left( {11} \right) = 0,2968253968 – 0,3287571662 = – 0,03193 \approx – 0,032\)