Rumus	\(\ddot a_x^{(m)} = {\ddot a_x} – \frac{{(m – 1)}}{{2m}}\) \({A_x} = 1 – d\,{\ddot a_x}\) \({A_x} = v\,{q_x} + v\,{p_x}\,{A_{x + 1}}\) \({\bar A_x} = \frac{i}{\delta }{A_x}\)
Step 1	\({\bar A_{70}} = \frac{i}{\delta }{A_{70}}\) \({\bar A_{70}} = \frac{{0,06}}{{\ln (1 + 0,06)}}{A_{70}}\)
	\(1.000{\bar A_{70}} = 530\) \({\bar A_{70}} = 0,53\)
	\(0,53 = \frac{{0,06}}{{\ln (1 + 0,06)}}{A_{70}}\) \({A_{70}} = \frac{{\ln (1 + 0,06)}}{{0,06}}\left( {0,53} \right)\) \({A_{70}} \cong {\rm{0}}{\rm{,51471}}\)
Step 2	\({A_{69}} = v\,{q_{69}} + v\,{p_{69}}\,{A_{70}}\) \({A_{69}} = \,\frac{{0,03}}{{(1 + 0,06)}} + \frac{{(1 – 0,03)}}{{(1 + 0,06)}}\,\left( {0,51471} \right)\) \({A_{69}} \cong {\rm{0}}{\rm{,49931}}\)
Step 3	\({A_{69}} = 1 – d\,{\ddot a_{69}}\) \(0,49931 = 1 – \frac{{0,06}}{{1,06}}{\ddot a_{69}}\) \({\ddot a_{69}} = \left( {1 – 0,49931} \right)\frac{{1,06}}{{0,06}}\) \({\ddot a_{69}} \cong {\rm{8}}{\rm{,84552}}\)
Step 4	\(\ddot a_{69}^{(2)} = {\ddot a_{69}} – \frac{{(2 – 1)}}{{2(2)}}\) \(\ddot a_{69}^{(2)} = (8,84552) – \frac{1}{4}\) \(\ddot a_{69}^{(2)} = {\rm{8}}{\rm{,59552}}\) \(\ddot a_{69}^{(2)} \cong {\rm{8}}{\rm{,59}}\)
Jawaban	C. 8,59