Pembahasan Ujian PAI: A50 – No. 17 – November 2016

Untuk \({\rm{ }}{\widehat q_x}\) \({\widehat q_{x + 1}} = \frac{{30}}{{170 – 22(1 – 0.5) + 32(1 – 0.25) – 28(1 – 0.75)}} = 0.068182\)

sehingga
\(_2{\widehat q_x} = 1 – {\widehat p_x} \cdot {\widehat p_{x + 1}}\) \(= 1 – \left( {1 – {{\widehat q}_x}} \right) \cdot \left( {1 – {{\widehat q}_{x + 1}}} \right)\) \(= 1 – \left( {1 – 0.139535} \right) \cdot \left( {1 – 0.068182} \right)\) \(= 0.198203\)